+0

# Percent yield help?

0
46
1

In   3Ca(OH)2  + 2 H3PO4  -> Ca3(PO4)2   + 6 H2O, find the percent yield if 31.6 g of calcium hydroxide produces 39.7 g of calcium phosphate.

Guest Dec 12, 2017
Sort:

#1
0

To find percent yield, we need to divide gotten value (39.7g of Ca3(PO4)2) by the theoretical yield.

To find Theoretical yield:

31.6g of Ca(OH)2 = roughly 0.42625... moles (divide by the average molar mass of Ca(OH)2 of 74.10g/mol)

For every 3 mol of Ca(OH)2, we should get 1 mol of Ca3(PO4)2 so if we divide 0.426... by 3 and multiply it by 1 we get how many moles of Ca3(PO4)2 we should theoretically get: roughly 0.14215... moles

We can then convert this back to grams by multiplying it by Ca3(PO4)2's molar mass of 310.18g/mol to get a theoretical yield of 44.09g

39.7g/44.09g * 100% = 90.04%

Guest Dec 12, 2017

### 5 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details