If you accelerate to a stop at -0.8m/s^2 by applying brakes, how far do you travel when your initial velocity is 10km/h?
+33615 Use v2 = u2 + 2as, where v = final speed (0), u = initial speed (10000/3600 m/s), a = acceleration (-0.8m/s2) and s = distance (metres)
0 = (10000/3600)2 -2*0.8*s
s = (100/36)2/1.6 m
$${\mathtt{s}} = {\frac{{\left({\frac{{\mathtt{100}}}{{\mathtt{36}}}}\right)}^{{\mathtt{2}}}}{{\mathtt{1.6}}}} \Rightarrow {\mathtt{s}} = {\mathtt{4.822\: \!530\: \!864\: \!197\: \!530\: \!9}}$$
s ≈ 4.8m
.
+33615 Use v2 = u2 + 2as, where v = final speed (0), u = initial speed (10000/3600 m/s), a = acceleration (-0.8m/s2) and s = distance (metres)
0 = (10000/3600)2 -2*0.8*s
s = (100/36)2/1.6 m
$${\mathtt{s}} = {\frac{{\left({\frac{{\mathtt{100}}}{{\mathtt{36}}}}\right)}^{{\mathtt{2}}}}{{\mathtt{1.6}}}} \Rightarrow {\mathtt{s}} = {\mathtt{4.822\: \!530\: \!864\: \!197\: \!530\: \!9}}$$
s ≈ 4.8m
.
