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The position of a squirrel running in a park is given by r⃗ =[(0.280m/s)t+(0.0360m/s2)t2]i^+ (0.0190m/s3)t3j^.

 

What is υx(t), the x-component of the velocity of the squirrel, as function of time?

a.) vx(t)=(0.0720m/s2)t

b.) vx(t)=(0.280m/s)t+(0.0720m/s2)t2     

c.) vx(t)=0.280m/s+(0.0720m/s2)t

d.) vx(t)=0.280m/s 

Guest Aug 5, 2017
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x(t) = 0.280t + 0.0360t2  so  vx(t) = 0.280 + 2*0.0360t → 0.280 + 0.0720t

 

(result c.))

Alan  Aug 5, 2017

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