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# please explain to me how come the graph/shape isnt moved to the left side as the equation is negative

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please explain to me how come the graph/shape isnt moved to the left side as the equation is negative

https://snag.gy/4AwGSV.jpg

YEEEEEET  Jan 6, 2018

#1
+5888
+2

There is the point  (0, 3)  on  y = f(x) ....  So we know that   f(0)  =  3  .

To produce the same  y  value on  y = f(x - 3) , we must input an  x  value such that  x - 3  = 0 .

When  x = 3 ,  y  =  f(x - 3)  =  f(3 - 3)  =  f(0)  =  3  ...So on  y = f(x - 3)  there is the point  (3, 3) .

At every point, the  x  value in  y = f(x - 3)  must be  3  greater than the  x  value in  y = f(x)  in order for both functions to produce the same  y  value.

hectictar  Jan 6, 2018
Sort:

#1
+5888
+2

There is the point  (0, 3)  on  y = f(x) ....  So we know that   f(0)  =  3  .

To produce the same  y  value on  y = f(x - 3) , we must input an  x  value such that  x - 3  = 0 .

When  x = 3 ,  y  =  f(x - 3)  =  f(3 - 3)  =  f(0)  =  3  ...So on  y = f(x - 3)  there is the point  (3, 3) .

At every point, the  x  value in  y = f(x - 3)  must be  3  greater than the  x  value in  y = f(x)  in order for both functions to produce the same  y  value.

hectictar  Jan 6, 2018

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