[1/5 (9)^5-4(9)^3+5(-7)]-[( 1/5 (-7)^5-4(-7)^3+5(-7)]
I am going to do it without a calculator!
\([\frac{ (9)^5}{5}-4(9)^3+5(-7)]\quad -\quad [\frac{ (-7)^5}{5}-4(-7)^3+5(-7)]\\ =[\frac{ (9)^5}{5}-4(9)^3-35]\quad -\quad [\frac{ -(7)^5}{5}+4*7^3-35]\\ =\frac{ (9)^5}{5}-4(9)^3-35 \quad +\quad \frac{ +(7)^5}{5}-4*7^3+35\\ =\frac{ (9)^5}{5}-4(9)^3 \quad +\quad \frac{ +(7)^5}{5}-4*7^3\\ =\frac{9^3}{5}(9^2-20) \quad +\quad \frac{ 7^3}{5}(7^2-20)\\ =\frac{729}{5}(61) \quad +\quad \frac{ 343}{5}(29)\\ =\frac{729}{5}(60)+ \frac{729}{5}+\quad \frac{ 343}{5}(30)-\frac{ 343}{5}\\ =729*12+ \frac{730}{5}-\frac{1}{5}+\quad 343*6-\frac{ 345}{5}+\frac{2}{5}\\ =729*12+ \frac{385}{5}+\quad 343*6+\frac{1}{5}\\ =729*12+ \frac{385}{5}+\quad 343*6+\frac{1}{5}\\ =729*12+77+\quad 343*6+\frac{1}{5}\\ =6*1458+77+\quad 343*6+\frac{1}{5}\\ =6*1801+77+\quad \frac{1}{5}\\ =10806+77+\quad \frac{1}{5}\\ =10883\frac{1}{5}\\ \)