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What is the equation of a parabola with (−2, 4)  as its focus and y = 6 as its directrix?

Guest May 30, 2017

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 #1
avatar+91219 
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What is the equation of a parabola with (−2, 4)  as its focus and y = 6 as its directrix?

 

Well it is concave down with a focal length of 1 and the vertex at (-2,5)

so

 

\((x-h)^2=4a(y-k)\\ (x+2)^2=4*-1*(y-5)\\ (x+2)^2=-4(y-5)\\\)

Melody  May 30, 2017
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1+0 Answers

 #1
avatar+91219 
+1
Best Answer

What is the equation of a parabola with (−2, 4)  as its focus and y = 6 as its directrix?

 

Well it is concave down with a focal length of 1 and the vertex at (-2,5)

so

 

\((x-h)^2=4a(y-k)\\ (x+2)^2=4*-1*(y-5)\\ (x+2)^2=-4(y-5)\\\)

Melody  May 30, 2017

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