Divide: (4y^3+2y^2-3y-4)/y
Are the equations y=2x+5 and y=5x+2 consistent, inconsistent, or dependent.
Solver by factoring: x^2=x+20 The two possible solutions possible are in the form of x=a and x=b. Evaluate a^2+b^2+a+b=
+280 y=2x+5 and y=5x+2 , set them equal to zero, and you get? I cant tell what your question is
+128474
(4y^3+2y^2-3y-4) / y =
(4y^3 / y) + (2y^2 / y - (3y) / y - (4) / y =
4y^2 + 2y - 3 - 4 / y
y = 2x + 5
y = 5x + 2
We have two lines with different slopes...........they will intersect at some point giving us one solution.....thus......this is a consistent system
x^2 = x + 20 rearrange as
x^2 - x - 20 = 0 fractor
(x - 5) ( x + 4) = 0
Setting both factors to 0 and solving for x, the two solutions are x = 5 and x = -4
So a^2 + b^2 + a + b = (5)^2 + (-4)^2 + 5 + - 4 = 42
