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How tall is a building that casts a 68​-ft shadow when the angle of elevation of the sun is 32°​?

Guest Apr 14, 2017
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 #1
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We can use the tangent here

 

tan (32)  = H / 68      where H is the building height.......multiply both sides by 68

 

68 * tan (32)   =  H   ≈  42.5 ft

 

 

cool cool cool

CPhill  Apr 14, 2017

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