A bag contains 11 candy bars: three cost 50 cents each, four cost $1 each and four cost $2 each. How many ways can 3 candy bars be selected from the 11 candy bars so that the total cost is more than $4?

Need *answer AND Explination* as soon as possible please!!!!! Thank you!!!!!!

Trinityvamp286
Jul 17, 2017

#1**+1 **

Looking at each candy bar as a unique item, we have C(11,3) = 165 total ways to choose any three of them

More than $4

$6 = Choose any three of the four $2 ones = C(4,3) = 4 ways

$5 = Choose any two of the four $2 ones and any one of the four $1 ones = C(4,2) * C(4,1) = 24 ways

$4.50 = Choose any two of the four $2 ones and any one of the three $.50 ones = C(4,2) * C(3,1) = 18 ways

So....the total ways are 4 + 24 + 18 = 46 ways

CPhill
Jul 17, 2017