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Thing 1 and Thing 2 were selling tickets to their upcoming play. They were two different types of tickets, adult and children. Thing 1 sold 3 adult tickets and 12 children's tickets for a total of \$70. Thing 2 made \$216 from the 12 adult and 12 children tickets it sold. What was the price of each type of ticket?

AngelicaMarrufo  Mar 2, 2015

#1
+81029
+5

Let x be the price of the children's ticket and y be the price of the adult...so we have

12x + 3y = 70

12x + 12y = 216    subtract the first equation from the second...this gives

9y = 156  divide both sides by 9

y = \$16.22    this is the approx cost of the adult ticket

And using the first equation to find the cost of the child's ticket, we have

12x + 3(16.22) = 70

12x + 48.66 = 70     subtract 48.66 from each side

12x = 21.34     divide both sides by 12

x = \$1.78  and this is the cost of the child's ticket

CPhill  Mar 2, 2015
Sort:

#1
+81029
+5

Let x be the price of the children's ticket and y be the price of the adult...so we have

12x + 3y = 70

12x + 12y = 216    subtract the first equation from the second...this gives

9y = 156  divide both sides by 9

y = \$16.22    this is the approx cost of the adult ticket

And using the first equation to find the cost of the child's ticket, we have

12x + 3(16.22) = 70

12x + 48.66 = 70     subtract 48.66 from each side

12x = 21.34     divide both sides by 12

x = \$1.78  and this is the cost of the child's ticket

CPhill  Mar 2, 2015

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