pls help me ; find, to the nearest centimetres, the length of the shadow of a 4 metre flagpole when the elevation of the sun is 58.

The shadow  length will be the adjacent side of a right triangle  and the height of the flagpole will be the side opposite the 58°  angle.....so we have

tan 58°   =  4 / S    where S is the shadow length

Multiply both sides by S  and divide both sides by tan 58°

S  =  4 / tan 58°   ≈  2.499 m  ≈  249.9  cm   ≈  250 cm