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farhan cycles the first part of a 150 km journey at an average speed of 35km/h. If he takes 4.5 hours for his entire journey, find the distance that he cycles.

Guest Feb 28, 2017
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 #1
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There is not enough info given here.  :(

 

 

 

I am jsut playing ....

 

 

farhan cycles the first part of a 150 km journey at an average speed of 35km/h.

x km at 35km/hour  that is  

\(\frac{x}{35} hours\)

 

If he takes 4.5 hours for his entire journey, find the distance that he cycles.

 

(150 - x)   km left

\(4.5 - \frac{x}{35} =\frac{ (4.5*35-x)}{35} = \frac{157.5-x}{35}\;\;hours\;\;left\)

 

\((150-x)\div \frac{157.5-x}{35}\;\;km/hour\\ \frac{35(150-x)}{157.5-x}\;\;km/hour\\\)

Melody  Feb 28, 2017
 #2
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Your question isn't very clear!. However, if we assume that Farhan covered the first 150 km at an average of 35 km/h, then it took too him: 150/35 =4 2/7 hours to cover that distance.
But the total distance was covered in 4 1/2 hours. Therefore, it took him: 4.5 - 4 2/7 =3/14 of an hour to cover the remaining distance. And since his average speed was 35 km/h for the first 150 km, will assume that the averge speed for the remaining distance was also 35 km/h. Therefore, the remaining distance would be: 35 km/h x 3/14 =7.50 km. So, the total distance cycled would be: 150 + 7.5 =157.5 km.

Guest Feb 28, 2017

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