Plz can someone help me solve this sum (7×8+72÷9)+(5 over 8 × 64 + 4 over 5 ×25)
alright lets destroy this math base!
$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right)$$
$$\left({\mathtt{56}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{40}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}\right)$$
$${\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\mathtt{60}} = {\mathtt{124}}$$
overall,
$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right) = {\mathtt{124}}$$
alright lets destroy this math base!
$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right)$$
$$\left({\mathtt{56}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{40}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}\right)$$
$${\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\mathtt{60}} = {\mathtt{124}}$$
overall,
$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right) = {\mathtt{124}}$$