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Plz can someone help me solve this sum (7×8+72÷9)+(5 over 8 × 64 + 4 over 5 ×25)

 Jul 29, 2015

Best Answer 

 #1
avatar+2972 
+5

alright lets destroy this math base!

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right)$$

$$\left({\mathtt{56}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{40}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}\right)$$

$${\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\mathtt{60}} = {\mathtt{124}}$$

overall,

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right) = {\mathtt{124}}$$

 Jul 29, 2015
 #1
avatar+2972 
+5
Best Answer

alright lets destroy this math base!

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right)$$

$$\left({\mathtt{56}}{\mathtt{\,\small\textbf+\,}}{\mathtt{8}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{40}}{\mathtt{\,\small\textbf+\,}}{\mathtt{20}}\right)$$

$${\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\mathtt{60}} = {\mathtt{124}}$$

overall,

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{8}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{72}}}{{\mathtt{9}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{5}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{64}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{4}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\mathtt{25}}\right) = {\mathtt{124}}$$

TitaniumRome Jul 29, 2015

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