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# Polynomial question

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question 2 & 3 i need help with please especially number 2 i get half way through and get confused with the turning points

Guest May 10, 2017
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#1
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The zeros for number three are 2 and -1

ParthForThree  May 10, 2017
#2
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For number two, a=-2, b=1, c=3, d=4

ParthForThree  May 10, 2017
#3
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A for number two is -1/6

ParthForThree  May 10, 2017
edited by ParthForThree  May 10, 2017
#4
+17616
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For number 2:  Since the zeros occur at -2, 1, 3, and 4, the values are:  a = -2, b = 1, c = 3, and d = 4.

This will create the function:  y  =  A(x + 2)(x -1)(x - 3)(x - 4)

To find the value of A:  Since the value of y = 4 when x = 0, place these into the function:

y  =  A(x + 2)(x -1)(x - 3)(x - 4)         --->         4  =  A(0 + 2)(0 -1)(0 - 3)(0 - 4)

Simplifying              --->         4  =  A(2)(-1)(-3)(-4)

4  =  A(-24)

Dividing by -24          --->      -1/6  =  A

geno3141  May 10, 2017
#5
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In question 2, you can't say explicitly what the values of a,b,c and d are.

You can say that a takes one of the values, -2,1,3 or 4, then,  having chosen(?) a value for a, b can take any of the three remaining values, and then c either of the two remaining values leaving d to be the last one.

Guest May 10, 2017

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