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Draw 7 cards. Find the probability of drawing 3 jacks and 4 fives.

Guest Jun 5, 2017

Best Answer 

 #1
avatar+90524 
+2

I am going to assume that order does not matter.

 

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

 

there are 52C7 possible combinations with no restrictions. 

nCr(52,7) = 133784560

 

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody  Jun 5, 2017
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1+0 Answers

 #1
avatar+90524 
+2
Best Answer

I am going to assume that order does not matter.

 

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

 

there are 52C7 possible combinations with no restrictions. 

nCr(52,7) = 133784560

 

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody  Jun 5, 2017

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