+0

# Probability Question

0
147
1

Draw 7 cards. Find the probability of drawing 3 jacks and 4 fives.

Guest Jun 5, 2017

#1
+91247
+2

I am going to assume that order does not matter.

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

there are 52C7 possible combinations with no restrictions.

nCr(52,7) = 133784560

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody  Jun 5, 2017
Sort:

#1
+91247
+2

I am going to assume that order does not matter.

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

there are 52C7 possible combinations with no restrictions.

nCr(52,7) = 133784560

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody  Jun 5, 2017

### 13 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details