#1**+2 **

I am going to assume that order does not matter.

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

there are 52C7 possible combinations with no restrictions.

nCr(52,7) = 133784560

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody
Jun 5, 2017

#1**+2 **

Best Answer

I am going to assume that order does not matter.

All the fives and 3 out of the 4 jacks - only one jack is missing so there are 4 combinations of cards that fit this description.

there are 52C7 possible combinations with no restrictions.

nCr(52,7) = 133784560

so that is

P(3 jacks and 4 fives) = 4 / 133784560

Melody
Jun 5, 2017