There are 22 sets of b***s numbered 11 through 1313 placed in a bowl. If 22 b***s are randomly chosen without replacement, find the probability that the b***s have the same number. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Guest Mar 11, 2017

#1**0 **

We have 22 [1313 - 11 + 1] = 28666 b***s

And we have 1313 - 11 + 1 = 1303 different possibilities for the 1st ball

So....the probability that the next 21 b***s we draw out match this number =

21! /[ 28665! / 28644!]

So....the total probability =

Ways to choose the 1st ball x probability of matching the 1st ball =

1303 * 21! * 28644! / 28665! =

1303

---------------------------------------------------------------------------------------------------------------------------

78138407065870996272303703695459299504064656359530399953320901718968820150

In other words.......highly improbable !!!!

CPhill
Mar 12, 2017