There are 22 sets of b***s numbered 11 through 1313 placed in a bowl. If 22 b***s are randomly chosen without replacement, find the probability that the b***s have the same number. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
We have 22 [1313 - 11 + 1] = 28666 b***s
And we have 1313 - 11 + 1 = 1303 different possibilities for the 1st ball
So....the probability that the next 21 b***s we draw out match this number =
21! /[ 28665! / 28644!]
So....the total probability =
Ways to choose the 1st ball x probability of matching the 1st ball =
1303 * 21! * 28644! / 28665! =
1303
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78138407065870996272303703695459299504064656359530399953320901718968820150
In other words.......highly improbable !!!!