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What is the probability of winning the jackpot if you have to match 5 numbers from 1 to 41, and then match one gold ball with the options of numbers being 1 through 31?

Guest Apr 4, 2015

Best Answer 

 #1
avatar+80866 
+5

Picking 5 numbers from 41 can be done in C(41,5) = 749,398 ways

And choosing another number from 31 can be done in 31 ways.....so....

749,398 x 31  = 23,231,338  ways

So  1 / 23,231,338  = 0.0000000430453037  = 0.00000430453037% chance of winning on one ticket.....not too good, is it ???

 

  

CPhill  Apr 4, 2015
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1+0 Answers

 #1
avatar+80866 
+5
Best Answer

Picking 5 numbers from 41 can be done in C(41,5) = 749,398 ways

And choosing another number from 31 can be done in 31 ways.....so....

749,398 x 31  = 23,231,338  ways

So  1 / 23,231,338  = 0.0000000430453037  = 0.00000430453037% chance of winning on one ticket.....not too good, is it ???

 

  

CPhill  Apr 4, 2015

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