1200 employees were surveyed about their meals preference in the cafeteria. The following

information was obtained: (write all the answers correct to 4 decimal places)

(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch?

(ii) What is the probability that a randomly chosen employee took dinner or prefers non vegetarian meal?

(iii) What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?

Guest Sep 29, 2017

#1**+1 **

**(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch? **

Let's get our ratio set up:

237/1200

Plug that into the calculator

237/1200 = 0.1975

So, part (i) has an answer of 0.1975

**(ii) What is the probability that a randomly chosen employee took dinner or prefers ****non-****vegetarian**** meal? **

In this, someone that chooses dinner AND chooses non-vegetarian meals are included.

First, let's add 206+200+191+182

206+200+191+182 = 779

So, our ratio will be 779/1200

Let's plug that into our calculator

779/1200 = 0.6491666666666667

Shorten that to 4 decimals and you get 0.6492

So, the answer for (ii) is 0.6492

**(iii) What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?**

In this, anyone who chooses a non-vegetarian meal is NOT included.

First, add 184+237+182

184+237+182 = 603

This will be the denominator of the ratio

The amount of people who chose breakfast is 184 people.

So, the ratio is 184/603

Plug this into the calculator.

184/603 = 0.3051409618573798

Shorten it to 4 decimal points and it becomes 0.3051

So, the answer to (iii) is 0.3051

I hope this helped!

rarinstraw1195
Sep 29, 2017

#1**+1 **

Best Answer

**(i) What is the probability that a randomly chosen employee prefers vegetarian meal and took lunch? **

Let's get our ratio set up:

237/1200

Plug that into the calculator

237/1200 = 0.1975

So, part (i) has an answer of 0.1975

**(ii) What is the probability that a randomly chosen employee took dinner or prefers ****non-****vegetarian**** meal? **

In this, someone that chooses dinner AND chooses non-vegetarian meals are included.

First, let's add 206+200+191+182

206+200+191+182 = 779

So, our ratio will be 779/1200

Let's plug that into our calculator

779/1200 = 0.6491666666666667

Shorten that to 4 decimals and you get 0.6492

So, the answer for (ii) is 0.6492

**(iii) What is the probability that a randomly chosen employee took breakfast given that he or she prefers vegetarian meal?**

In this, anyone who chooses a non-vegetarian meal is NOT included.

First, add 184+237+182

184+237+182 = 603

This will be the denominator of the ratio

The amount of people who chose breakfast is 184 people.

So, the ratio is 184/603

Plug this into the calculator.

184/603 = 0.3051409618573798

Shorten it to 4 decimal points and it becomes 0.3051

So, the answer to (iii) is 0.3051

I hope this helped!

rarinstraw1195
Sep 29, 2017