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Calculate;

1+3i / 1-3i ,

|7±7i| ,

√4(1+ i) ,

^4√4(1-i),

And write the result in the standardform Re  z+i  in z 

 Oct 24, 2014

Best Answer 

 #1
avatar+23246 
+5

To simplify  (1 + 3i) / (1 - 3i)  multiply both the numerator and the denominator by the conjugate of the denominator.

The conjugate of  1 - 3i  is  1 + 3i.

So, you need to simplify:  [ (1 + 3i)(1 + 3i) ] / [ (1 - 3i)(1 + 3i) ]     Use FOIL.

-----------------------------------

The absolute value of a complex number is the distance that the point, when graphed is from the origin.

Label the point  x + yi  and use the Pytharoean Theorem:  r²  =  x² +  y²

When  x = 7  and  y = 7, what is the value of r?

When  x = 7  and  y = -7, what is the value of r?

-----------------------------------

By √4(1 + i), do you mean 2(1 + i)?  If so, use the distributive law.

-----------------------------------

By  "^4√4", do you mean the fourth root of 4?  4^(1/4)  =  (2^2)^(1/4)  =  2^(1/2)  =  √2.

√2(1 - i)  =  √2 - √2i

 Oct 24, 2014
 #1
avatar+23246 
+5
Best Answer

To simplify  (1 + 3i) / (1 - 3i)  multiply both the numerator and the denominator by the conjugate of the denominator.

The conjugate of  1 - 3i  is  1 + 3i.

So, you need to simplify:  [ (1 + 3i)(1 + 3i) ] / [ (1 - 3i)(1 + 3i) ]     Use FOIL.

-----------------------------------

The absolute value of a complex number is the distance that the point, when graphed is from the origin.

Label the point  x + yi  and use the Pytharoean Theorem:  r²  =  x² +  y²

When  x = 7  and  y = 7, what is the value of r?

When  x = 7  and  y = -7, what is the value of r?

-----------------------------------

By √4(1 + i), do you mean 2(1 + i)?  If so, use the distributive law.

-----------------------------------

By  "^4√4", do you mean the fourth root of 4?  4^(1/4)  =  (2^2)^(1/4)  =  2^(1/2)  =  √2.

√2(1 - i)  =  √2 - √2i

geno3141 Oct 24, 2014

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