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How many zeroes does f(x)=(x-c)squared+d have if d>0?

Guest Jun 26, 2017

Best Answer 

 #1
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Set the whole thing to 0. i.e. f(x) = 0.

\(f(x) = 0 \\ (x-c)^2 + d = 0\\ (x-c)^2 = -d\)

It has no real solutions. Therefore it have no zeroes.

MaxWong  Jun 26, 2017
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1+0 Answers

 #1
avatar+6810 
+2
Best Answer

Set the whole thing to 0. i.e. f(x) = 0.

\(f(x) = 0 \\ (x-c)^2 + d = 0\\ (x-c)^2 = -d\)

It has no real solutions. Therefore it have no zeroes.

MaxWong  Jun 26, 2017

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