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# Radical Form Alg 2- I don't need much help, Just a confirmation I'm doing it right

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(4x^3y^2) 3/10

What is the expression in simplest radical form?

Sqrt 432

Am I right?

Simplify. ^3 Sqrt125x^21y^33

Am I right?

Simplify. 9 Sqrt56x^7y^12

Am I right?

Guest Oct 5, 2017
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#1
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$$\sqrt{432}\,=\,\sqrt{2*2*2*2*3*3*3}\,=\,\sqrt{2*2}*\sqrt{2*2}*\sqrt{3*3}*\sqrt3\,=\,2*2*3*\sqrt3$$

$$=\,12\sqrt3$$          Right!

Is this the third one??

$$\sqrt[3]{125x^{21}y^{33}}\,\,=\,(125x^{21}y^{33})^{\frac13}\,=\,125^{\frac13}x^{\frac{21}{3}}y^{\frac{33}{3}}\,=\,5x^{7}y^{11}$$

$$9\sqrt{56x^7y^{12}}\,=\,9\sqrt{2*2*2*7*x*x^6*y^{12}}\,=\,9*\sqrt{2*2}*\sqrt{2*7*x}*\sqrt{x^6}*\sqrt{y^{12}}\\~\\=\,9*2*\sqrt{14x}*x^3*y^6\,=\,18x^3y^6\sqrt{14x}$$

hectictar  Oct 8, 2017

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