+0  
 
0
38
4
avatar

 

Thereis x. If you add 

30/7

 to it, from the sum you get subtract

22/7

, and then subtract that difference from

59/7

, then you will get

19/7
what is x?
smiley

Guest Nov 12, 2017

Best Answer 

 #3
avatar+5263 
+1

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

hectictar  Nov 12, 2017
Sort: 

4+0 Answers

 #1
avatar
0

PLEASE SOLVE!!!!!!!!!!!!!!!!!!!!!!

Guest Nov 12, 2017
 #2
avatar
0

hint:answer is not 70/7 or 10

Guest Nov 12, 2017
 #3
avatar+5263 
+1
Best Answer

\(\frac{59}{7}-[(x+\frac{30}{7})-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-[x+\frac{30}{7}-\frac{22}{7}]=\frac{19}{7} \\~\\ \frac{59}{7}-x-\frac{30}{7}+\frac{22}{7}=\frac{19}{7} \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}=\frac{19}{7}+x \\~\\ \frac{59}{7}-\frac{30}{7}+\frac{22}{7}-\frac{19}{7}=x \\~\\ \frac{32}{7}=x\)

hectictar  Nov 12, 2017
 #4
avatar
+1

thanks

Guest Nov 12, 2017

4 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details