how do i make y the subject of the equation the its : x=y-1/y ???
Y = 1 / (1 - X)
If the equation is x = (y - 1)/y then Guest #1 is correct.
If it is x = y - 1/y then it is quadratic in y and we have: \(y = \frac{x\pm \sqrt{x^2+4}}{2}\)
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