r is not equal to plus or minus 2, (r squared - 5r + 6) over (r squared - 4 = ?
$$\dfrac{r^2-5r+6}{r^2-4}\qquad r\ne\pm2\\\\ =\dfrac{(r-3)(r-2)}{(r-2)(r+2)}\\\\ =\dfrac{r-3}{r+2}\\\\$$