Is this what you mean? 2sin2x=-sqrt(3)???. if so, then:
Solve for x:
2 sin(2 x) = -sqrt(3)
Divide both sides by 2:
sin(2 x) = -sqrt(3)/2
Take the inverse sine of both sides:
2 x = (4 π)/3 + 2 π n_1 for n_1 element Z
or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z
Divide both sides by 2:
x = (2 π)/3 + π n_1 for n_1 element Z
or 2 x = (5 π)/3 + 2 π n_2 for n_2 element Z
Divide both sides by 2:
Answer: |
| x = (2 π)/3 + π n_1 for n_1 element Z
or x = (5 π)/6 + π n_2 for n_2 element Z
