Roll two dice. What is the probability to roll a sum of greater than 9 and/or a multiple of 6
Fraction answer plz
Sums > 9 include
10 = 3 ways to do this
11 = 2 ways to do this
12 = 1 way to do this
6 ways to roll a sum > 9
Multiples of 6
6 = 5 ways to do this
12 = 1 way to do this
6 ways to roll a multiple of 6
And we have 36 possible outcomes
So, N (sum > 9 and multiple of 6) = 1 way [rolling a 12 ]
And the P(sum > 9 and multiple of 6) = 1/36
And N ( sum > 9 or multiple of 6 ) = N(sum > 9) + N(multiple of 6) - N(sum > 9 and multiple of 6) =
6 + 6 - 1 = 11 ways
So ... P(sum > 9 or multiple of 6) = 11/36