+0

# roots

0
53
1
+1364

Find the roots of the equation: $$6x^2+3x=0$$

tertre  Dec 30, 2017

#1
+64
+4

Hello, tertre...

$$6x^2+3x=0, x(6x+3)=0,$$ so one root of the equation is 0, and the other is $$6x+3=0, 6x=-3, x=\frac{-3}{6}, \frac{-1}{2}$$

azsun  Dec 30, 2017
Sort:

#1
+64
+4
$$6x^2+3x=0, x(6x+3)=0,$$ so one root of the equation is 0, and the other is $$6x+3=0, 6x=-3, x=\frac{-3}{6}, \frac{-1}{2}$$