+0

# Science

0
45
1
+33

Mel rolls a .01kg marble down a ramp and off the edge of a table with a horizontal velocity of 1.2m/s. The marble hits a target placed .51m from the table's edge. How high is the table?

KingChris  Dec 20, 2017
Sort:

#1
+80910
+1

The horizontal velocity is unaffected by the drop..   also ....the weight of the marble is irrelevant..so....

The time it takes to drop  =  d / r  =    .51 m / 1.2 m/s   =  .425 s

So......the height of the table can be found  as

H  =  vi * t   +  (1/2) a  * t^2

Where

H  =  the table height

vi =  the intital vertical velocity =  0

t  =  time to drop  =   .425 s

a  =  acceleration due to gravity =  9.81 m/s^2

So we have

H  =  0 * .425s +  (1/2) (9.81m/s^2) * (.425s)^2

H  ≈   .886 m

CPhill  Dec 20, 2017

### 31 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details