+33 Mel rolls a .01kg marble down a ramp and off the edge of a table with a horizontal velocity of 1.2m/s. The marble hits a target placed .51m from the table's edge. How high is the table?
+128474 The horizontal velocity is unaffected by the drop.. also ....the weight of the marble is irrelevant..so....
The time it takes to drop = d / r = .51 m / 1.2 m/s = .425 s
So......the height of the table can be found as
H = vi * t + (1/2) a * t^2
Where
H = the table height
vi = the intital vertical velocity = 0
t = time to drop = .425 s
a = acceleration due to gravity = 9.81 m/s^2
So we have
H = 0 * .425s + (1/2) (9.81m/s^2) * (.425s)^2
H ≈ .886 m
