+0  
 
+3
554
2
avatar+546 

25 1/2 (all one number. 25 and 1 are not nominators to 2)

 

(sqrt9xy^2)^4

 Jul 28, 2014

Best Answer 

 #1
avatar+4473 
+13

25 1/2 as in 25^(1/2) --> sqrt(25) = 5.

 

(sqrt9xy^2)^4 --> (sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)

(sqrt9xy^2)(sqrt9xy^2) = 9x^2y^4

Now, we can just square this term [9x^2y^4] since we have another (sqrt9xy^2)(sqrt9xy^2) -->

(9x^2y^4)(9x^2y^4) = 81x^4y^8.

An easier way is to just distribute the ^4 to each of the terms -->

(sqrt9xy^2)^4 = (sqrt9)^4*x^4*(y^2)^4 = 81x^4y^8.

***************************************************************************************************

EDITED: First answer.

 Jul 28, 2014
 #1
avatar+4473 
+13
Best Answer

25 1/2 as in 25^(1/2) --> sqrt(25) = 5.

 

(sqrt9xy^2)^4 --> (sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)(sqrt9xy^2)

(sqrt9xy^2)(sqrt9xy^2) = 9x^2y^4

Now, we can just square this term [9x^2y^4] since we have another (sqrt9xy^2)(sqrt9xy^2) -->

(9x^2y^4)(9x^2y^4) = 81x^4y^8.

An easier way is to just distribute the ^4 to each of the terms -->

(sqrt9xy^2)^4 = (sqrt9)^4*x^4*(y^2)^4 = 81x^4y^8.

***************************************************************************************************

EDITED: First answer.

AzizHusain Jul 28, 2014
 #2
avatar+118587 
+3

I don't know what the first question means but the second has  been well answered.

Thanks Aziz  

 Jul 29, 2014

4 Online Users

avatar