How to solve: 60 = 30 sin 60 (3-d) + 30 ?????? where d is the phase shift. Hope you can help.
y = a sin k(x-d) + c
Thanks.
60 = 30 sin 60 (3-d) + 30 subtract 30 from each side
30 = 30sin (180 - 60d) divide both sides by 30
1= sin (180 - 60d) the sine will = 1 at 90°
Therefore ..... 180 - 60d = 90 subtract 180 from each side
-60d = - 90 divide both sides by -60
d = 9/6 = 3/2