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solve [4*(x^2)]+12x-12=0

 
Guest Oct 12, 2017
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Solve for x:
4 x^2 + 12 x - 12 = 0

 

Divide both sides by 4:
x^2 + 3 x - 3 = 0

 

Add 3 to both sides:
x^2 + 3 x = 3

 

Add 9/4 to both sides:
x^2 + 3 x + 9/4 = 21/4

 

Write the left hand side as a square:
(x + 3/2)^2 = 21/4

 

Take the square root of both sides:
x + 3/2 = sqrt(21)/2 or x + 3/2 = -sqrt(21)/2

 

Subtract 3/2 from both sides:
x = sqrt(21)/2 - 3/2 or x + 3/2 = -sqrt(21)/2

 

Subtract 3/2 from both sides:
x = sqrt(21)/2 - 3/2       or         x = -3/2 - sqrt(21)/2

 
Guest Oct 12, 2017

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