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solve for h

SA=2pir^2+2pirh

Guest Apr 22, 2017

Best Answer 

 #1
avatar+4164 
+3

SA = 2πr2  + 2πrh

 

Subtract 2πr2 from both sides of the equation.

SA - 2πr2 = 2πrh

 

Divide through by 2πr .

SA/(2πr) - r = h

hectictar  Apr 22, 2017
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1+0 Answers

 #1
avatar+4164 
+3
Best Answer

SA = 2πr2  + 2πrh

 

Subtract 2πr2 from both sides of the equation.

SA - 2πr2 = 2πrh

 

Divide through by 2πr .

SA/(2πr) - r = h

hectictar  Apr 22, 2017

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