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Solve for x:

 \([\frac{x^2+2x+3}{x+4}=x+5]\)

tertre  Mar 5, 2017
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 #1
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+5

[ x^2 + 2x + 3] / [ x + 4]  =  [ x + 5]      multiply both sides by x + 4

 

x^2 + 2x + 3  =  x^2 + 9x + 20     subtract x^2 from both sides

 

2x + 3  = 9x + 20       subtract, 9x, 3 from both sides

 

-7x  = 17     divide both sides by -7

 

x  = -17 / 7

 

 

cool cool cool

CPhill  Mar 5, 2017

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