#2**+10 **

Since both equations = 1, we have

x + y + z = 2xy - z^2 or, alternatively

x + y - 2xy + z^2 + z = 0

As Melody indicates, because we have more variables than equations, there are infinitely many solutions.....

The graph of this is a "two-sheeted" hyperboloid....... here it is displayed in WolframAlpha

CPhill
Sep 14, 2014

#2**+10 **

Best Answer

Since both equations = 1, we have

x + y + z = 2xy - z^2 or, alternatively

x + y - 2xy + z^2 + z = 0

As Melody indicates, because we have more variables than equations, there are infinitely many solutions.....

The graph of this is a "two-sheeted" hyperboloid....... here it is displayed in WolframAlpha

CPhill
Sep 14, 2014