A car travelling from Town X to Town Y passed a van halfway.The van was travelling in the opposite direction at a uniform speed of 40 km/h.2.5 hours later,the car reached Town Y and the van was still 25 km from Town X.Find the distance between Town X and Town Y.
A car travelling from Town X to Town Y passed a van halfway.The van was travelling in the opposite direction at a uniform speed of 40 km/h.2.5 hours later,the car reached Town Y and the van was still 25 km from Town X.Find the distance between Town X and Town Y.
Average speed =Distance /Time
Let the distance between between the 2 towns =D
Let the average speed of the car =S. But we have:
(1/2D) / 2.5 =S. And we also have:
40 =[(1/2D) - 25] / 2.5, Solve for D, S
D = 250 Km - distance between towns X and Y
S =50 Km/h - average speed of the car
+14903 A car travelling from Town X to Town Y passed a van halfway.The van was travelling in the opposite direction at a uniform speed of 40 km/h.2.5 hours later,the car reached Town Y and the van was still 25 km from Town X.Find the distance between Town X and Town Y.
\(\frac{s}{2}=2.5h\cdot40\frac{km}{h}+25km\)
\(s=2(2.5h\cdot40\frac{km}{h}+25km)=200km+50km\)
\(\large s=250km\)
\(The \ cities \ X \ and \ Y \ are \ 250\ km \ apart.\)
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+128407
A car travelling from Town X to Town Y passed a van halfway.The van was travelling in the opposite direction at a uniform speed of 40 km/h.2.5 hours later,the car reached Town Y and the van was still 25 km from Town X.Find the distance between Town X and Town Y.
Call the car's rate, R
And the rate it travels times the time it travels = R * 2.5 = the halway distance between the towns = (1)
And the rate the van travels (40 km/hr ) times 2.5 hrs + 25 km = (1)
So....setting these equal, we have
R * 2.5 = 40* ( 2.5) + 25 simplify
2.5 R = 100 + 25
2.5R = 125 divide both sides by 2.5
R = 50 km/hr
Then....this the rate of the car........so......the distance between the towns = 2* (2.5)* 50 = 250 km
