$${\sqrt[{{\mathtt{{\mathtt{3}}}}}]{{{\mathtt{a}}}^{{\mathtt{2}}}}}{\mathtt{\,\times\,}}{\sqrt[{{\mathtt{{\mathtt{4}}}}}]{{\mathtt{a}}}}$$
3√(a2) x 4√a =
a^(2/3) x a^(1/4 ) =
a^(2/3 + 1/4) =
a^(11/12) =
12√(a11) in radical form
