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"The mean time taken by admin staff in a certain company to log on to their computer network is 70 seoncs with a standard deviation of 6 seconds. Assuming these times are normally distirbuted, what percentage of admin staff would have logged on with a minute" I have no idea how to attempt this question, any tips? thank you for any help.

Guest Apr 26, 2017
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 #1
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standard deviation = sqrt(n p *(1-p))

 

where n = amount of people and p = percentage of deviation

 

for explanation

 

source; http://www.stat.ufl.edu/~mmeece/Spring2023/Spring2012/practiceexam2answers_2012.pdf 

Guest Apr 26, 2017
 #2
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Approximately 4.8% according to Wolfram Alpha:

 

Alan  Apr 26, 2017
edited by Alan  Apr 26, 2017
 #3
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I've assumed your question was how many people had logged on in up to a minute above. If you meant something else, there might still be enough information in the image to answer the question.

Alan  Apr 26, 2017

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