+118608 I'll take it from here MathsGod
64+6y= 2
You want the y by itself so to start with you will get 6y by itself.
How can you get rid of the 64 from the left side?
Well you could take it away, but if you do it on the left you have to do it one the right as well.
64-64+6y=2-64
0+6y=-62
6y=-62
6*y=-62
now you need to get rid of the *6 on the left side
The inverse of *6 is divide by 6 and divide is the same as a fraction.
So you have to divide by 6. But remember to do it on BOTH sides. The equation must stay balanced
$$\\\frac{6y}{6}=\frac{-62}{6}\\\\
y=\frac{-62}{6}\\\\
y=\frac{-31}{3}\\\\
y=-10\frac{1}{3}\\\\$$
+4709 x = 8
8x+6y=2
8x = 8*x = 8*8
64+6y= 2
Do the inverse.
2+64=66
6y=66
y=66/6
y=11
+118608 I'll take it from here MathsGod
64+6y= 2
You want the y by itself so to start with you will get 6y by itself.
How can you get rid of the 64 from the left side?
Well you could take it away, but if you do it on the left you have to do it one the right as well.
64-64+6y=2-64
0+6y=-62
6y=-62
6*y=-62
now you need to get rid of the *6 on the left side
The inverse of *6 is divide by 6 and divide is the same as a fraction.
So you have to divide by 6. But remember to do it on BOTH sides. The equation must stay balanced
$$\\\frac{6y}{6}=\frac{-62}{6}\\\\
y=\frac{-62}{6}\\\\
y=\frac{-31}{3}\\\\
y=-10\frac{1}{3}\\\\$$
