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Suppose that $455 is invested 2.88% interest compounded continuously. How much is in the account after 15 years?

Deathstroke_rule  Feb 26, 2017
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A   = Pe^(r*t)     ....note...... r = 2.88%   =   .0288   

 

So

 

A   = 455e^(.0288 * 15)   ≈ $700.85

 

 

cool cool cool

CPhill  Feb 26, 2017

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