tanø=3.62/4: ø=?
42.1451
A radius vector in a circle with r = 4 intersects the applied tangent
at height 3.62.
So
\(\ ∅ = 8\)
\(tan \ α = \frac{3.62}{4}\)
\(α = atan\ \frac{3.62}{4}=42°\ 8' \ 42''\)
!