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tanø=3.62/4: ø=?

Guest Feb 28, 2017
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 #1
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42.1451

Guest Feb 28, 2017
 #2
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tanø=3.62/4: ø=?

 

A radius vector in a circle with r = 4 intersects the applied tangent

at height 3.62.

 

So

 

\(\ ∅ = 8\)

 

\(tan \ α = \frac{3.62}{4}\)

 

\(α = atan\ \frac{3.62}{4}=42°\ 8' \ 42''\)

 

laugh  !

asinus  Feb 28, 2017
edited by asinus  Feb 28, 2017

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