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tan 78'40"

 Feb 27, 2015

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 #1
avatar+118609 
+5

tan(0+78/60+40/3600)

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{78}}}{{\mathtt{60}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{40}}}{{\mathtt{3\,600}}}}\right)} = {\mathtt{0.022\: \!887\: \!200\: \!781}}$$

 Feb 27, 2015
 #1
avatar+118609 
+5
Best Answer

tan(0+78/60+40/3600)

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{0}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{78}}}{{\mathtt{60}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{40}}}{{\mathtt{3\,600}}}}\right)} = {\mathtt{0.022\: \!887\: \!200\: \!781}}$$

Melody Feb 27, 2015

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