if i have a right triangle how do i solve for one of the angles when i am giving the opposite and the adjacent to it?

Guest Mar 7, 2017

#1**+1 **

\(\tan(\text{ the angle }) = \frac{ (\text{ length of side opposite the angle })}{(\text{ length of side adjacent the angle })}\)

Just plug in the information that you have and solve for whatever you need.

The reverse of tan is arctan. (This can also be expressed as atan or tan^{-1}.)

\(( \text{ the angle }) = \arctan(\frac{ (\text{ length of side opposite the angle })}{(\text{ length of side adjacent the angle })})\)

The reverse of sin is arcsin (or asin or sin^{-1}).

The reverse of cos is arccos (or acos or cos^{-1}).

Another thing to remember is that the adjacent side can never be the hypotenuse.

hectictar
Mar 7, 2017