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tan(½x-20º)=1

Guest May 4, 2017
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If you just want the answer for    \(\tan(\frac12x-20º)\)  in the first quadrant...

 

\(\tan(\frac12x-20º)=1\\~\\ \frac12x-20º=\arctan(1) \\~\\ \frac12x-20º=45º \\~\\ \frac12x=45º+20º \\~\\ \frac12x=65º \\~\\ x=65º*2\\~\\x=130º\)

 

If you want the general solution please say so smiley

hectictar  May 4, 2017

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