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What is the sum of the digits in the terminating decimal representation of the fraction \(\frac{4321}{5^7\cdot2^8}\) ?

tertre  Mar 14, 2017

Best Answer 

 #1
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+5

   4321/[5^7.2^8] = 0.00021605, so the sum of the digits:

2+1+6+5 =14.

Guest Mar 14, 2017
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2+0 Answers

 #1
avatar
+5
Best Answer

   4321/[5^7.2^8] = 0.00021605, so the sum of the digits:

2+1+6+5 =14.

Guest Mar 14, 2017
 #2
avatar+76972 
+5

(4321)/ (5^7 * 2^8)  =  0.00021605

 

I'll let you do the math......

 

 

cool cool cool

CPhill  Mar 14, 2017

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