+284 THANKS CPHILLLLLLL!!!!! I need help!!
△ABC∼△EFG .
Given m∠B=48° and m∠G=61° , what is m∠A ?
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+9466 Since △ABC ∼ △EFG , m∠C = m∠G .
Since m∠G = 61° , m∠C = 61°
Now we know two of the angles in triangle ABC ....
m∠B = 48° and m∠C = 61° .
How can we find the measure of the third angle, angle A ?
Remember that the sum of the angles in every triangle = 180°
m∠A + m∠B + m∠C = 180° Plug in what we know....
m∠A + 48° + 61° = 180° Subtract 61° and 48° from both sides of the equation.
m∠A = 180° - 61° - 48°
m∠A = 71°
+9466 Since △ABC ∼ △EFG , m∠C = m∠G .
Since m∠G = 61° , m∠C = 61°
Now we know two of the angles in triangle ABC ....
m∠B = 48° and m∠C = 61° .
How can we find the measure of the third angle, angle A ?
Remember that the sum of the angles in every triangle = 180°
m∠A + m∠B + m∠C = 180° Plug in what we know....
m∠A + 48° + 61° = 180° Subtract 61° and 48° from both sides of the equation.
m∠A = 180° - 61° - 48°
m∠A = 71°
