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3 = e^0.1r, find r

 Oct 24, 2016

Best Answer 

 #3
avatar+36916 
+5

oops.....  Melody accidentally used LOG for the last step instead of the natural ln   ....

10*ln(3) = 10.9861

 Oct 24, 2016
 #1
avatar+118609 
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3 = e^0.1r, find r

 

Perhaps you mean   3 = e^(0.1r), find r

 

\(3 = e^{0.1r}\\ ln3=0.1r\\ r=ln3/0.1\\ r=10ln3\)

 

10*log(3) = 4.7712125471966244

 Oct 24, 2016
 #2
avatar+36916 
+5

Take the natural ln of both sides;

ln(3)=ln(e^(.1r) )

1.09861 = .1r      Divide both sides by .1

10.9861= r

 Oct 24, 2016
 #3
avatar+36916 
+5
Best Answer

oops.....  Melody accidentally used LOG for the last step instead of the natural ln   ....

10*ln(3) = 10.9861

ElectricPavlov Oct 24, 2016
 #4
avatar+118609 
0

Thanks EP   blush

Melody  Oct 24, 2016
 #5
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+5

This formula asks the question: How long does it take for $1 to grow to $3 @ 10% compounded continuously? The answer, just as has been calculated above, is just under 11 years. So, r here =number of years. "n" is normally used to denote number of years, and "r" to denote the "interest rate", but has been reversed here.

 Oct 24, 2016

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