The Dallas Cowboys started the season with a record of 2-7 ( 2wins, 7 losses). How many consecutive games must they win in order to raise th

If you need an equation:  let  x  represent the number of games needed

Then, the number of wins will be x + 2

and, the total number of games will be x + 7

You need:  (x + 2)/(x + 7)  =  0.56

Cross-multiplying:  x + 2  =  0.56(x + 7)

--->                      x + 2  =  0.56x + 3.92

--->                0.44x + 2  =  2.92

--->                      0.44x  =  0.92

--->                            x  =  2.1 games

Winning the next 2 will get you close; winning the next 3 will get you "at least 56%".

OH EVEN I KNOW THIS ONE NEVER! XD anyways lets just start off by saying this is a pretty accurate win/loss for the cowboys. Anyway you cant get 56% if 7 games is the highest limit. You can only get 57% which is a 4-7 win/loss streak by dividing 4/7 of course a 3.99/7 can get you 56% but come on... 3.99 wins. Hence! MAking this question illogical! And therefor it cannot be solved correctly if corresponding to said example!

Thanks Geno - I like this question and answer.    

im callin geno ah liaa! How did you get 56% without it breaking into a fraction?!

This is a theoretical impossibilty.......everyone knows that, if the Cowboys start 2 - 7, they'll finish up at 4-12......thus.....56% is out of the question.......!!!!!

BECAUSE.......THE COWBOYS SUCK  !!!!!!