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 The function $f(x,y)$ accepts an ordered pair as input and gives another ordered pair as output. It is defined according to the following rules: If $x > 4$, $f(x,y) = (x - 4,y)$. If $x \le 4$ but $y > 4$, $f(x,y) = (x,y - 4)$. Otherwise, $f(x,y) = (x + 5, y + 6)$. A robot starts by moving to the point $(1,1)$. Every time it arrives at a point $(x,y)$, it applies $f$ to that point and then moves to $f(x,y)$. If the robot runs forever, how many different points will it visit? 

Guest Jul 24, 2017
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 #1
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The function f(x,y) accepts an ordered pair as input and gives another ordered pair as output.
It is defined according to the following rules:
If x > 4, f(x,y) = (x - 4,y).
If x less equal 4 but y > 4, f(x,y) = (x,y - 4).
Otherwise, f(x,y) = (x + 5, y + 6).
A robot starts by moving to the point (1,1).
Every time it arrives at a point (x,y),
it applies f to that point and then moves to f(x,y).
If the robot runs forever,
how many different points will it visit?

 

 

laugh

heureka  Jul 24, 2017
edited by heureka  Jul 24, 2017
 #2
avatar+26366 
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This question was asked and answered here: https://web2.0calc.com/questions/i-need-some-help_8#r1 

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Alan  Jul 24, 2017

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