The points (7,13) and (-3,-11) are at the ends of a diameter. Find an equation for this circle.
The radius = (1/2)√[ (-3-7)^2 + (-11 - 13)^2] = (1/2)√[10^2 + 24^2] = (1/2)√676 = (1/2)26 = 13
And the center is at [ ( 7 -3) / 2 , (13-11) / 2 ] = [4/2, 2.2] = (2, 1) and the equation is....
(x - 2)^2 + (y - 1)^2 = 13^2 ..... or......
(x - 2)^2 + (y - 1)^2 = 169
Here's a graph........https://www.desmos.com/calculator/rx1yothteb
The radius = (1/2)√[ (-3-7)^2 + (-11 - 13)^2] = (1/2)√[10^2 + 24^2] = (1/2)√676 = (1/2)26 = 13
And the center is at [ ( 7 -3) / 2 , (13-11) / 2 ] = [4/2, 2.2] = (2, 1) and the equation is....
(x - 2)^2 + (y - 1)^2 = 13^2 ..... or......
(x - 2)^2 + (y - 1)^2 = 169
Here's a graph........https://www.desmos.com/calculator/rx1yothteb