The slope of the function f(x)= (3x-5)^7 has an integer value at x= 2. Use some sort of numerical method to determine what it is.
f(x) = (3x -5)^7 ....the derivative of this function will give us the slope at any x value.....so...
f ' (x) = [7(3x - 5)^6 ]* (3) = 21(3x -5)^6 ....... so.......
f ' (2) = 21(3(2) - 5)^6 = 21(6 -5)^6 = 21(1)^6 = 21
And when x = 2, y = 1.......her's a graph of the tangent line to the function at that point...https://www.desmos.com/calculator/x9cy77qjdk
f(x) = (3x -5)^7 ....the derivative of this function will give us the slope at any x value.....so...
f ' (x) = [7(3x - 5)^6 ]* (3) = 21(3x -5)^6 ....... so.......
f ' (2) = 21(3(2) - 5)^6 = 21(6 -5)^6 = 21(1)^6 = 21
And when x = 2, y = 1.......her's a graph of the tangent line to the function at that point...https://www.desmos.com/calculator/x9cy77qjdk